2.1 Kw Suntech 175 mono, Classic 200, Trace SW 4024 ( 15 years old but brand new out of sealed factory box Jan. 2015), Bogart Tri-metric, 700 ah @24 volt AGM battery bank. Plenty of Baja Sea of Cortez sunshine.
Got mine off eBay.
It's called a SunStalker (one word) manual solar tracker. There's another item of the same name out there but you should be able to locate it online.
It is not hard to make one... You just need to decide what is "best" and "good" for you...To calculate the energy from the sun, offset by the angle of the panel to the sun is Cosine Angle (degrees) ...So, a panel that is pointing directly at the sun is Cos 0 degrees = 1.00 ... I.e., 100% of the available sun's energy hits the panel.Cosine 10 degrees = 0.98 or 98% of the available energy.Say you decide 90% of the solar energy is the boundary between Best and Good... That would be invCos 0.9 = 26 degreesAnd if you decide that 0.71 (71%) is good/bad boundary, that would be 45 degrees.Here is a handy chart if you don't have an engineering calculator:https://www.mathwarehouse.com/trigonometry/sine-cosine-tangent-chart.phpCosine is the angle of the ratio of opposite over hypotenuse.One way to lay out what you want (i.e., a circle at 26 degrees) would be to use a protractor to make the angle and use the distance between the "sight" and the target, then draw a vertical line to the angle. That distance would be the radius of the circle.Or you can use the Tangent function. Tangent is the angle of the opposite over the adjacent. From above Cos 26d = 0.90 as our "best/good" target line, Tan 26 degrees = 0.488 and the radius would be:Tan (d) = O/AO = Tan (d) * AExample of Tan (26 degrees) = 0.488Use A = 5 inches between peephole sight and targetO = Tan (26) * 5 inches = 0.488 * 5 " = 2.44 inch radius circle for targetIf I remember my trig... -Bill
It seems to me something like a long nail at right angles through a piece of wood would do much the same thing. Tilt the panel to make the shadow disappear at noon.