We pump about 6,400 gallons a day from 3 wells with tracked solar arrays and a experimental diesel.

raysubtropicalraysubtropical Posts: 5Registered Users ✭✭
Our current fuel consumption is 4 hours per gallon with about a 1,000 watt load (grundfos submersible with 260' of head or 113 PSI) using an early kubota water cooled two cylinder engine and a 4KW meccalte generator head. My current interest is to improve on this....so Ive combined an early air cooled single yamaha diesel to a ST-5 chinese head. (i call it my frankenstein generator). Last night i ran this 4 pole head at about 1800RPM for 13 hours on 1.75 gallons of diesel. Same load but no power robbing water pump or electric radiator fan. Since I'm still in shock about the numbers...i'm repeating the test tonight. We operate an off-grid fruit farm and would like to share our information and experience. Pictures on request...till I can figure out how to post them.  

Comments

  • mike95490mike95490 Posts: 7,611Solar Expert ✭✭✭✭
    I think you have made a mistake with the consumption measurement.
    I run a single cyl diesel, water cooled (thermosiphon, no pump) and a 4 pole ST-5 head, and consume a bit over a quart an hour, with 2600w load.  While it's not the most efficient 1930's model, it's not horrible either.  Figure a properly loaded diesel produces 3/3ds power,
    1/3 into the alternator, 1/3 heat lost out the exhaust, 1/3 in the cooling .
    Powerfab top of pole PV mount | Listeroid 6/1 w/st5 gen head | XW6048 inverter/chgr | Iota 48V/15A charger | Morningstar 60A MPPT | 48V, 800A NiFe Battery (in series)| 15, Evergreen 205w "12V" PV array on pole | Midnight ePanel | Grundfos 10 SO5-9 with 3 wire Franklin Electric motor (1/2hp 240V 1ph ) on a timer for 3 hr noontime run - Runs off PV ||
    || Midnight Classic 200 | 10, Evergreen 200w in a 160VOC array ||
    || VEC1093 12V Charger | Maha C401 aa/aaa Charger | SureSine | Sunsaver MPPT 15A

    solar: http://tinyurl.com/LMR-Solar
    gen: http://tinyurl.com/LMR-Lister ,

  • mcgivormcgivor Posts: 1,635Registered Users ✭✭✭✭
    edited May 15 #3
    Our current fuel consumption is 4 hours per gallon with about a 1,000 watt load (grundfos submersible with 260' of head or 113 PSI) using an early kubota water cooled two cylinder engine and a 4KW meccalte generator head. My current interest is to improve on this....so Ive combined an early air cooled single yamaha diesel to a ST-5 chinese head. (i call it my frankenstein generator). Last night i ran this 4 pole head at about 1800RPM for 13 hours on 1.75 gallons of diesel. Same load but no power robbing water pump or electric radiator fan. Since I'm still in shock about the numbers...i'm repeating the test tonight. We operate an off-grid fruit farm and would like to share our information and experience. Pictures on request...till I can figure out how to post them.  
    Yamaha? Or is that Yanmar with auto mistake spelling?  Diesel fuel contains around 37 Kw per US gallon, 1.75 gallons would be 64.75 Kw, at 20% efficiency of the diesel engine, the approximate available energy would be 12.9Kw. The 1Kw load over 13 hours is 13 Kw, so the numbers are close, add a few points to the efficiency percentage,  sounds about right, but is the improvement in efficiency due to the Kubota operating outside it's peak in the torque curve? As an example my pickup is a six speed manual 2.5 liter diesel, if driven at 80 Kmh in 6th.gear, it will consume more fuel than if driven in 5th. according to the on board graphic display, in 5th it displays 5.2 l/100 Km (45 MPG/US gallon )in 6th it's 6.7l/100Km (35 MPG/US gallon ) the RPM in 6th. is ~1750RPM, in 5th. It's ~2000 RPM, which is where the torque peak is, actually it's wider due,to variable geometry turbo, but the point is operating below or above the torque peak is inefficient. Most likely the setup on your frankenstein generator is a good match with the diesel operating in its sweet spot and thanks for sharing your observations. 
      1500W, 6× Schutten 250W Poly panels , Schneider 150 60 CC, Schneider SW 2524 inverter, 8×T105 GC 24V nominal 

  • EstragonEstragon Posts: 2,215Registered Users ✭✭✭✭
    Roughly... 129000 btu/gal of diesel x 1.75 gals used ÷ 3.4 btu/watt ÷ 13hrs = ~5kw/hr ?

    1kw/hr = 20% thermal efficiency?
    Off-grid.  
    Main daytime system ~4kw panels into 2xMNClassic150 370ah 48v bank 2xOutback 3548 inverter 120v + 240v autotransformer
    Night system ~1kw panels into 1xMNClassic150 700ah 12v bank morningstar 300w inverter
  • mcgivormcgivor Posts: 1,635Registered Users ✭✭✭✭
    edited May 15 #5
    12900 BTU= 37 KwW 
    12900 × 1.75= 225750 btu
    225750btu = 66Kw
    20%☆ of 66Kw is 13.2 Kw
    13 hours × 1Kw☆☆ = 13 Kw
    all figures rounded off.

    ☆20% is diesel engine efficiency 
    ☆☆pump load

      1500W, 6× Schutten 250W Poly panels , Schneider 150 60 CC, Schneider SW 2524 inverter, 8×T105 GC 24V nominal 

  • Dave AngeliniDave Angelini Posts: 3,630Solar Expert ✭✭✭✭
    Where are you located and what type of tracking are you running? Please send the pix as I am always interested in tracking and have been tracking for quite some time. My e-mail is below. Subtropics is where please?
    "we go where power lines don't" Sierra Mountains near Mariposa/Yosemite CA
     http://members.sti.net/offgridsolar/
    E-mail [email protected]

  • jonrjonr Posts: 949Solar Expert ✭✭✭✭
    edited May 16 #7
    > but the point is operating below or above the torque peak is inefficient

    A diesel's best efficiency (BSFC) operating point is typically around the rpm that produces max torque and at about 80% of max torque - but it doesn't have to be right at it.    This point might produce about 1/2 of the rated HP.
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