No, in series (connecting the positive of one to the negative of the other) the amperage remains the same and the voltage increases.
In essence you are just building a bigger battery, a 6 volt battery is really 3 - 2 volt cells hooked up in series, your just making a battery with 6 cells.
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It's not 100% clear to me what the OP was asking, so I could see two possible answers:
"No": Two 6V golf cart batteries, each, say with 220 Amp Hours, wired in Series, will give you 220 Amp Hours (at 12V).
"Yes" : Two 6V golf cart batteries will give you a hell of a lot more amp hours than a single 12V battery of similar size (as these tend to max out at about 100 Amp Hours).
voltage times watts = amps by putting your batteries in series, it allows you to put the same amps through the wires but because you doubled the volts, you have doubled the power
I like to tinker... 5 and a half running motorcycles and a pile O'parts
Comments
No, in series (connecting the positive of one to the negative of the other) the amperage remains the same and the voltage increases.
In essence you are just building a bigger battery, a 6 volt battery is really 3 - 2 volt cells hooked up in series, your just making a battery with 6 cells.
You double the voltage = 2x the power
You double the current = 2x the power
You take two batteries in series, you get:
P = 2*Voltage * Current
You take same two batteries in parallel, you get:
P = Voltage * 2*Current
Same amount of power (or energy if you use Amp*Hours instead of Amps for the current).
-Bill
"No": Two 6V golf cart batteries, each, say with 220 Amp Hours, wired in Series, will give you 220 Amp Hours (at 12V).
"Yes" : Two 6V golf cart batteries will give you a hell of a lot more amp hours than a single 12V battery of similar size (as these tend to max out at about 100 Amp Hours).
-Rodger-
Let's see if I can get this right - it's been a while since I had this in school.
- Volts = Potential Energy/Charge = N*m/C = kg*m2/(A*s3)
- Amps = Charge / Time = 1C/s
- Watts = J/S = N*m/S = (kg*m2)/s3
So, in the example above:"voltage times watts" = (kg*m2)/(A*s3) * (kg*m2)/s3 = (kg2*m4)/(a*s6) : not what we want.
Instead if you look at power (watts), does it equal VA?
Watts = (kg*m2)/s3 = VA ?
Let's look at VA
VA = V * A = (kg*m2)/(A*s3) * (C/s)
= kg*m2*C/(A*s3)
Substituting in that we know 1A = 1C/s we get
= kg*m2*(A/S)/(A*s3)
And the A's and one of the S's cancel out, leaving us with
VA = (kg*m2)/s3
e.g, the definition of Power in Watts.
opps, you are right in any case, by doubling the voltage you can double the watts and still have the same amps
-Rodger-