Charging question
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Dailypix
Registered Users Posts: 11 ✭✭
I have 4 6 volt batteries wired to give 24 volts. They are rated at 428AH each. Suppose I have no load whatsoever. I even turn off the inverter. I get 5 hours sun.
How many watts solar panels do I need to completely charge the batteries in 1 day?
Also with the batteries wired this way is the capacity of the bank 428AH or is it 4 X 428AH.
i guess what I am trying to learn is how powerful I need the panels to be for a battery bank this size in order to charge it up fairly quickly. Assume I have good MPPT charge controller. I want to learn how to do the math minus the load.
regards
How many watts solar panels do I need to completely charge the batteries in 1 day?
Also with the batteries wired this way is the capacity of the bank 428AH or is it 4 X 428AH.
i guess what I am trying to learn is how powerful I need the panels to be for a battery bank this size in order to charge it up fairly quickly. Assume I have good MPPT charge controller. I want to learn how to do the math minus the load.
regards
Comments

Send a message to BB,Bill or wait, I'm sure he will read your request sooner or later, he has a wealth of information I couldn't approach regarding charging, hours of sun, loss percentages and so on.
Your battery capacity buy the way is 428Ah @ 24v, you would multiply if they were in parallel which would be 1712Ah @ 6v
1500W, 6× Schutten 250W Poly panels , Schneider MPPT 60 150 CC, Schneider SW 2524 inverter, 400Ah LFP 24V nominal battery with Battery Bodyguard BMS
Second system 1890W 3 × 300W No name brand poly, 3×330 Sunsolar Poly panels, Morningstar TS 60 PWM controller, no name 2000W inverter 400Ah LFP 24V nominal battery with Daly BMS, used for water pumping and day time air conditioning.
5Kw Yanmar clone single cylinder air cooled diesel generator for rare emergency charging and welding. 
Thank you

I suppose to simplify the question I am looking for the formula to calculate the watt hours for a 428 amp hour 24 volt system and will I have to multiply it times 4 because it is made up of 4 batteries.

I am hereJust had to get to laptop computer so I can type on a real keyboard and bigger screen....
For the batteries, when you add batteries in series, the voltage adds. When you add batteries in parallel, the Amp*Hours adds... For a couple of examples (as Migivor says): 4x 6 volt batteries in series @ 428 AH = 24 volts @ 428 AH
 4x 6 volt batteries in parallel @ 428 AH = 6 volt @ 1,712
 2series x 2parallel of 6 volt @ 428 AH = 12 volts @ 856 AH
 24 volts * 428 AH = 6 volts * 1,712 AH = 12 volts * 856 AH = 10,272 Watt*Hours
MPPT or PWM controller, it does not "matter" for this first set of math... The choices of MPPT/PWM, bus voltage, etc. depends on size of system, distances, cost issues, power needs, etc.... And we can choose that stuff later after we work out the basics.
I don't like to do a bunch of "what if" calculationsIt tends to make things confusing. Since I do not know anything about your loads, power needs, where the system is, etc... I will start the design with your battery bank, and we can go from there (normally loads drive the sizing of the battery bank).
Just to give you an idea of what loads could be supported by your proposed battery bank (using our, relatively conservative, off grid rules of thumbs), for an AC inverter based system, with 2 days of storage (no sun), and 50% maximum battery discharge (longer battery life for Lead Acid batteries): 24 volts * 428 AH * 0.85 AC inverter eff * 1/2 days of storage * 0.50 maximum discharge = 2,183 Watt*Hours per day
 428 AH * 1,000 Watts per 200 AH (at 24 volt battery bank) = 2,140 Watt maximum AC inverter (or AC loads) recommended (or smaller)
Next, charging... We suggest 5% to 13% rate of charge5% is good for a weekend system use, or seasonal (sunny summer usage). For a full time off grid system, suggest 10%+ rate of charge to keep battery happy and not agonize about energy usage every day. 428 AH * 29 volts charging * 1/0.77 panel+controller deratings * 0.05 rate of charge = 806 Watt array minimum
 428 AH * 29 volts charging * 1/0.77 panel+controller deratings * 0.10 rate of charge = 1,612 Watt array nominal
 428 AH * 29 volts charging * 1/0.77 panel+controller deratings * 0.13 rate of charge = 2,096 Watt array "cost effective" maximum
However, with solar power, you can only charge when you have sun. So say you are near Brampton Ontario Canada:
http://www.solarelectricityhandbook.com/solarirradiance.htmlBrampton
Measured in kWh/m2/day onto a solar panel set at a 46° angle from vertical:
Average Solar Insolation figures
(For best yearround performance)
Lets say you are "doomed" to using a genset during the 3 winter monthsThat leaves February at 3.50 hours of sun per day as the "break even" month (note this are usually 20 year average sun based on weather conditions, etc.). And we use the daily load of 2,140 Watt*Hour per day nominal load (some days more, some days lessThe "blessings of using the free sun power":Jan Feb Mar Apr May Jun 2.71
3.50
4.04
4.50
4.75
5.12
Jul Aug Sep Oct Nov Dec 5.24
4.98
4.58
3.68
2.47
2.24
 2,140 Watt*Hours of AC power * 1/0.52 AC off grid system eff * 1/3.50 hours of sun (Feb break even month) = 1,176 Watt array minimum (Feb break even).
Does this get you started/give you some ideas (I can give you the inverse of some equations, or you can do the algebra too).
Note that Solar power is accurate to within 10% or so (don't get down to the 0.4 watt numbersI just used all the digits so you can repeat my math and not have roundoff errors in further calculations, and you can follow where the numbers are used). A 1,612 Watt array is about the same as a 1,451 Watt array (of course, more array is more energyBut it is close enough for our needs).
And the above rules of thumbs are just to get us "close" to a workable system without going into a 5 page post with 5x more math and hand waving discussions. There is nothing "magic" about the above numbers and they can be moved around based on your actual power needs (day time vs night time loads, winter or summer usage vs full time, size of loads and surge currentssuch as starting a well pump, etc.).
But the above should get you into the ball park.
Bill
Near San Francisco California: 3.5kWatt Grid Tied Solar power system+small backup genset
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